Base | Representation |
---|---|
bin | 100010000001001110… |
… | …1011110011100011011 |
3 | 20222120101020101000011 |
4 | 1010002131132130123 |
5 | 2144104231202324 |
6 | 53321125422351 |
7 | 5164250263612 |
oct | 1040235363433 |
9 | 228511211004 |
10 | 73055725339 |
11 | 28a8a063813 |
12 | 121aa26a9b7 |
13 | 6b7354025c |
14 | 37707a6879 |
15 | 1d78a10c94 |
hex | 110275e71b |
73055725339 has 2 divisors, whose sum is σ = 73055725340. Its totient is φ = 73055725338.
The previous prime is 73055725321. The next prime is 73055725357. The reversal of 73055725339 is 93352755037.
It is a balanced prime because it is at equal distance from previous prime (73055725321) and next prime (73055725357).
It is an emirp because it is prime and its reverse (93352755037) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 73055725339 - 211 = 73055723291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 73055725292 and 73055725301.
It is not a weakly prime, because it can be changed into another prime (73055725399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36527862669 + 36527862670.
It is an arithmetic number, because the mean of its divisors is an integer number (36527862670).
Almost surely, 273055725339 is an apocalyptic number.
73055725339 is a deficient number, since it is larger than the sum of its proper divisors (1).
73055725339 is an equidigital number, since it uses as much as digits as its factorization.
73055725339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2976750, while the sum is 49.
The spelling of 73055725339 in words is "seventy-three billion, fifty-five million, seven hundred twenty-five thousand, three hundred thirty-nine".
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