Base | Representation |
---|---|
bin | 10100110000000110011101… |
… | …010111000001010000000011 |
3 | 102222010222112100100111002202 |
4 | 110300012131113001100003 |
5 | 43430302041413130201 |
6 | 522035112211303415 |
7 | 25136531322126656 |
oct | 2460063527012003 |
9 | 388128470314082 |
10 | 91266400130051 |
11 | 27097954621793 |
12 | a2a00588aab6b |
13 | 3bc04ccc86c03 |
14 | 1877462aa989d |
15 | a840adadec6b |
hex | 53019d5c1403 |
91266400130051 has 4 divisors (see below), whose sum is σ = 91266441746832. Its totient is φ = 91266358513272.
The previous prime is 91266400130041. The next prime is 91266400130107. The reversal of 91266400130051 is 15003100466219.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 91266400130051 - 226 = 91266333021187 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 91266400129987 and 91266400130014.
It is not an unprimeable number, because it can be changed into a prime (91266400130011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17324420 + ... + 21969713.
It is an arithmetic number, because the mean of its divisors is an integer number (22816610436708).
Almost surely, 291266400130051 is an apocalyptic number.
91266400130051 is a deficient number, since it is larger than the sum of its proper divisors (41616781).
91266400130051 is a wasteful number, since it uses less digits than its factorization.
91266400130051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41616780.
The product of its (nonzero) digits is 38880, while the sum is 38.
The spelling of 91266400130051 in words is "ninety-one trillion, two hundred sixty-six billion, four hundred million, one hundred thirty thousand, fifty-one".
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