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94331211212837 is a prime number
BaseRepresentation
bin10101011100101100110010…
…010101011110100000100101
3110100222222100022002220011102
4111130230302111132200211
544331010310032302322
6532343054333245445
725604130231401144
oct2534546225364045
9410888308086142
1094331211212837
112806970757a1a5
12a6b602b933885
134083519bc8c31
1419419253bb75b
15ad8b88122792
hex55cb3255e825

94331211212837 has 2 divisors, whose sum is σ = 94331211212838. Its totient is φ = 94331211212836.

The previous prime is 94331211212747. The next prime is 94331211212857. The reversal of 94331211212837 is 73821211213349.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79618394251396 + 14712816961441 = 8922914^2 + 3835729^2 .

It is a cyclic number.

It is not a de Polignac number, because 94331211212837 - 216 = 94331211147301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 94331211212791 and 94331211212800.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (94331211212857) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47165605606418 + 47165605606419.

It is an arithmetic number, because the mean of its divisors is an integer number (47165605606419).

Almost surely, 294331211212837 is an apocalyptic number.

It is an amenable number.

94331211212837 is a deficient number, since it is larger than the sum of its proper divisors (1).

94331211212837 is an equidigital number, since it uses as much as digits as its factorization.

94331211212837 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 435456, while the sum is 47.

The spelling of 94331211212837 in words is "ninety-four trillion, three hundred thirty-one billion, two hundred eleven million, two hundred twelve thousand, eight hundred thirty-seven".