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94331211213377 is a prime number
BaseRepresentation
bin10101011100101100110010…
…010101011110101001000001
3110100222222100022002220220102
4111130230302111132221001
544331010310032312002
6532343054333252145
725604130231402545
oct2534546225365101
9410888308086812
1094331211213377
112806970757a646
12a6b602b934055
134083519bc9258
1419419253bba25
15ad8b88122a02
hex55cb3255ea41

94331211213377 has 2 divisors, whose sum is σ = 94331211213378. Its totient is φ = 94331211213376.

The previous prime is 94331211213271. The next prime is 94331211213419. The reversal of 94331211213377 is 77331211213349.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77432238594481 + 16898972618896 = 8799559^2 + 4110836^2 .

It is a cyclic number.

It is not a de Polignac number, because 94331211213377 - 224 = 94331194436161 is a prime.

It is not a weakly prime, because it can be changed into another prime (94331211213077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47165605606688 + 47165605606689.

It is an arithmetic number, because the mean of its divisors is an integer number (47165605606689).

Almost surely, 294331211213377 is an apocalyptic number.

It is an amenable number.

94331211213377 is a deficient number, since it is larger than the sum of its proper divisors (1).

94331211213377 is an equidigital number, since it uses as much as digits as its factorization.

94331211213377 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 571536, while the sum is 47.

The spelling of 94331211213377 in words is "ninety-four trillion, three hundred thirty-one billion, two hundred eleven million, two hundred thirteen thousand, three hundred seventy-seven".