Base | Representation |
---|---|
bin | 10110000101001010101101… |
… | …011111000011011101011111 |
3 | 110201211211100200210101212012 |
4 | 112011022231133003131133 |
5 | 100212041111004132232 |
6 | 542312405332501435 |
7 | 26312055615060131 |
oct | 2605125537033537 |
9 | 421754320711765 |
10 | 97112121161567 |
11 | 28a410237626a6 |
12 | aa84b90a7a87b |
13 | 42258313ccb35 |
14 | 19da374ad7051 |
15 | b361984ba9b2 |
hex | 5852ad7c375f |
97112121161567 has 2 divisors, whose sum is σ = 97112121161568. Its totient is φ = 97112121161566.
The previous prime is 97112121161543. The next prime is 97112121161593. The reversal of 97112121161567 is 76516112121179.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 97112121161567 - 216 = 97112121096031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (97112121121567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48556060580783 + 48556060580784.
It is an arithmetic number, because the mean of its divisors is an integer number (48556060580784).
Almost surely, 297112121161567 is an apocalyptic number.
97112121161567 is a deficient number, since it is larger than the sum of its proper divisors (1).
97112121161567 is an equidigital number, since it uses as much as digits as its factorization.
97112121161567 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 317520, while the sum is 50.
The spelling of 97112121161567 in words is "ninety-seven trillion, one hundred twelve billion, one hundred twenty-one million, one hundred sixty-one thousand, five hundred sixty-seven".
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