Base | Representation |
---|---|
bin | 10110010011111111110101… |
… | …000110110000110001111111 |
3 | 110212110020212010212111220022 |
4 | 112103333311012300301333 |
5 | 100330240224340033203 |
6 | 544412510440042355 |
7 | 26445514234225121 |
oct | 2623776506606177 |
9 | 425406763774808 |
10 | 98131230002303 |
11 | 292a4248073453 |
12 | b00a5a64633bb |
13 | 429a973553914 |
14 | 1a33810d2b211 |
15 | b5294261aa38 |
hex | 593ff51b0c7f |
98131230002303 has 2 divisors, whose sum is σ = 98131230002304. Its totient is φ = 98131230002302.
The previous prime is 98131230002287. The next prime is 98131230002317. The reversal of 98131230002303 is 30320003213189.
It is a strong prime.
It is an emirp because it is prime and its reverse (30320003213189) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 98131230002303 - 24 = 98131230002287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (98131230002503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49065615001151 + 49065615001152.
It is an arithmetic number, because the mean of its divisors is an integer number (49065615001152).
Almost surely, 298131230002303 is an apocalyptic number.
98131230002303 is a deficient number, since it is larger than the sum of its proper divisors (1).
98131230002303 is an equidigital number, since it uses as much as digits as its factorization.
98131230002303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23328, while the sum is 35.
The spelling of 98131230002303 in words is "ninety-eight trillion, one hundred thirty-one billion, two hundred thirty million, two thousand, three hundred three".
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