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99252847 = 4633
BaseRepresentation
bin1011110101001…
…11101001101111
320220202120022101
411322213221233
5200402042342
613503155531
72313430621
oct572475157
9226676271
1099252847
1151031151
12292a5ba7
13177416c5
14d278c11
158aa83b7
hex5ea7a6f

99252847 has 4 divisors (see below), whose sum is σ = 99467680. Its totient is φ = 99038478.

The previous prime is 99252823. The next prime is 99252859. The reversal of 99252847 is 74825299.

The cubic root of 99252847 is 463.

It is a perfect power (a cube), and thus also a powerful number.

It is not a de Polignac number, because 99252847 - 27 = 99252719 is a prime.

It is a super-2 number, since 2×992528472 = 19702255275210818, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 99252797 and 99252806.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (99252047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214138 + ... + 214600.

It is an arithmetic number, because the mean of its divisors is an integer number (24866920).

Almost surely, 299252847 is an apocalyptic number.

99252847 is a deficient number, since it is larger than the sum of its proper divisors (214833).

99252847 is an frugal number, since it uses more digits than its factorization.

99252847 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1389 (or 463 counting only the distinct ones).

The product of its digits is 362880, while the sum is 46.

The square root of 99252847 is about 9962.5723083951.

The spelling of 99252847 in words is "ninety-nine million, two hundred fifty-two thousand, eight hundred forty-seven".

Divisors: 1 463 214369 99252847