9953280000 has 510 divisors, whose sum is σ = 37261388164. Its totient is φ = 2654208000.

The previous prime is 9953279989. The next prime is 9953280011. The reversal of 9953280000 is 823599.

It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.

It is a Jordan-Polya number, since it can be written as 6! ⋅ (5!)³ ⋅ (2!)³.

It is an interprime number because it is at equal distance from previous prime (9953279989) and next prime (9953280011).

It is a Harshad number since it is a multiple of its sum of digits (36).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 29 ways as a sum of consecutive naturals, for example, 1990655998 + ... + 1990656002.

Almost surely, 2^9953280000 is an apocalyptic number.

9953280000 is a gapful number since it is divisible by the number (90) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 9953280000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18630694082).

9953280000 is an abundant number, since it is smaller than the sum of its proper divisors (27308108164).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

9953280000 is an frugal number, since it uses more digits than its factorization.

9953280000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67 (or 10 counting only the distinct ones).

The product of its (nonzero) digits is 19440, while the sum is 36.

The square root of 9953280000 is about 99766.1265159673. The cubic root of 9953280000 is about 2151.0742783474.

Multiplying 9953280000 by its product of nonzero digits (19440), we get a 5-th power (193491763200000 = 720⁵).

9953280000 divided by its product of nonzero digits (19440) gives a cube (512000 = 80³).

The spelling of 9953280000 in words is "nine billion, nine hundred fifty-three million, two hundred eighty thousand".