9992000033 has 2 divisors, whose sum is σ = 9992000034. Its totient is φ = 9992000032.

The previous prime is 9992000017. The next prime is 9992000077. The reversal of 9992000033 is 3300002999.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5507420944 + 4484579089 = 74212^2 + 66967^2 .

It is a cyclic number.

It is not a de Polignac number, because 9992000033 - 2⁴ = 9992000017 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 9991999957 and 9992000002.

It is not a weakly prime, because it can be changed into another prime (9992000533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4996000016 + 4996000017.

It is an arithmetic number, because the mean of its divisors is an integer number (4996000017).

Almost surely, 2^9992000033 is an apocalyptic number.

It is an amenable number.

9992000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

9992000033 is an equidigital number, since it uses as much as digits as its factorization.

9992000033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13122, while the sum is 35.

The square root of 9992000033 is about 99959.9921618644. The cubic root of 9992000033 is about 2153.8600232133.

The spelling of 9992000033 in words is "nine billion, nine hundred ninety-two million, thirty-three", and thus it is an aban number.