Base | Representation |
---|---|
bin | 1011111010111… |
… | …01110110001001 |
3 | 20222011110222212 |
4 | 11331131312021 |
5 | 201044432423 |
6 | 13531154505 |
7 | 2322656414 |
oct | 575356611 |
9 | 228143885 |
10 | 99999113 |
11 | 514a08a5 |
12 | 295a5a35 |
13 | 17943296 |
14 | d3d0b7b |
15 | 8ba4578 |
hex | 5f5dd89 |
99999113 has 2 divisors, whose sum is σ = 99999114. Its totient is φ = 99999112.
The previous prime is 99999103. The next prime is 99999131. The reversal of 99999113 is 31199999.
Together with next prime (99999131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 95491984 + 4507129 = 9772^2 + 2123^2 .
It is an emirp because it is prime and its reverse (31199999) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-99999113 is a prime.
It is not a weakly prime, because it can be changed into another prime (99999103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49999556 + 49999557.
It is an arithmetic number, because the mean of its divisors is an integer number (49999557).
Almost surely, 299999113 is an apocalyptic number.
It is an amenable number.
99999113 is a deficient number, since it is larger than the sum of its proper divisors (1).
99999113 is an equidigital number, since it uses as much as digits as its factorization.
99999113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 177147, while the sum is 50.
The square root of 99999113 is about 9999.9556499017. The cubic root of 99999113 is about 464.1575109941.
The spelling of 99999113 in words is "ninety-nine million, nine hundred ninety-nine thousand, one hundred thirteen".
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