Numbers n that set a new record in the ratio σ(n)/n. more
The superabundant numbers up to 10
15 :
1,
2,
4,
6,
12,
24,
36,
48,
60,
120,
180,
240,
360,
720,
840,
1260,
1680,
2520,
5040,
10080,
15120,
25200,
27720,
55440,
110880,
166320,
277200,
332640,
554400,
665280,
720720,
1441440,
2162160,
3603600,
4324320,
7207200,
8648640,
10810800,
21621600,
36756720,
61261200,
73513440,
122522400,
147026880,
183783600,
367567200,
698377680,
735134400,
1102701600,
1163962800,
1396755360,
2327925600,
2793510720,
3491888400,
6983776800,
13967553600,
20951330400,
27935107200,
41902660800,
48886437600,
80313433200,
160626866400,
321253732800,
481880599200,
642507465600,
963761198400,
1124388064800,
1927522396800,
2248776129600,
3373164194400,
4497552259200,
4658179125600,
6746328388800,
9316358251200,
13974537376800,
18632716502400,
27949074753600,
32607253879200,
55898149507200,
65214507758400,
97821761637600,
130429015516800,
144403552893600,
195643523275200,
288807105787200,
433210658680800,
577614211574400,
866421317361600.
Distribution of the remainders when the numbers in this family are divided by n=2, 3,..., 11. (I took into account 1000 values, from 1 to 8.74⋅10149).
n\r | 0 | 1 |
2 | 999 | 1 | 2 |
3 | 997 | 2 | 1 | 3 |
4 | 997 | 1 | 2 | 0 | 4 |
5 | 992 | 3 | 2 | 1 | 2 | 5 |
6 | 997 | 1 | 1 | 0 | 1 | 0 | 6 |
7 | 986 | 3 | 2 | 2 | 2 | 2 | 3 | 7 |
8 | 991 | 1 | 1 | 0 | 6 | 0 | 1 | 0 | 8 |
9 | 988 | 1 | 1 | 4 | 1 | 0 | 5 | 0 | 0 | 9 |
10 | 992 | 1 | 2 | 0 | 2 | 0 | 2 | 0 | 1 | 0 | 10 |
11 | 978 | 3 | 3 | 1 | 5 | 2 | 3 | 0 | 2 | 1 | 2 |
A pictorial representation of the table above
Imagine to divide the members of this family by a number n and compute the remainders. Should they be uniformly distributed, each remainder from 0 to n-1 would be obtained in about (1/n)-th of the cases. This outcome is represented by a white square. Reddish (resp. bluish) squares represent remainders which appear more (resp. less) frequently than 1/n.