Base | Representation |
---|---|
bin | 1001000110001101111111… |
… | …1001010111101011001001 |
3 | 1022102020001020221110002001 |
4 | 2101203133321113223021 |
5 | 2302334444144122213 |
6 | 33135020235311001 |
7 | 2051436536036320 |
oct | 221433771275311 |
9 | 38366036843061 |
10 | 10002440223433 |
11 | 3207013819aa9 |
12 | 1156658bab461 |
13 | 5772c2888608 |
14 | 26819925d0b7 |
15 | 1252be2b21dd |
hex | 918dfe57ac9 |
10002440223433 has 32 divisors (see below), whose sum is σ = 11616184419840. Its totient is φ = 8436026880000.
The previous prime is 10002440223427. The next prime is 10002440223439. The reversal of 10002440223433 is 33432204420001.
It is an interprime number because it is at equal distance from previous prime (10002440223427) and next prime (10002440223439).
It is a cyclic number.
It is not a de Polignac number, because 10002440223433 - 237 = 9865001269961 is a prime.
It is not an unprimeable number, because it can be changed into a prime (10002440223439) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 440217513 + ... + 440240233.
It is an arithmetic number, because the mean of its divisors is an integer number (363005763120).
Almost surely, 210002440223433 is an apocalyptic number.
It is an amenable number.
10002440223433 is a deficient number, since it is larger than the sum of its proper divisors (1613744196407).
10002440223433 is a wasteful number, since it uses less digits than its factorization.
10002440223433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26809.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 10002440223433 its reverse (33432204420001), we get a palindrome (43434644643434).
The spelling of 10002440223433 in words is "ten trillion, two billion, four hundred forty million, two hundred twenty-three thousand, four hundred thirty-three".
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