100121113113 has 32 divisors (see below), whose sum is σ = 152965017600. Its totient is φ = 57062434176.

The previous prime is 100121113087. The next prime is 100121113117. The reversal of 100121113113 is 311311121001.

It is a de Polignac number, because none of the positive numbers 2^k-100121113113 is a prime.

It is a super-2 number, since 2×100121113113² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100121113092 and 100121113101.

It is not an unprimeable number, because it can be changed into a prime (100121113117) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17430720 + ... + 17436462.

It is an arithmetic number, because the mean of its divisors is an integer number (4780156800).

Almost surely, 2^100121113113 is an apocalyptic number.

It is an amenable number.

100121113113 is a deficient number, since it is larger than the sum of its proper divisors (52843904487).

100121113113 is a wasteful number, since it uses less digits than its factorization.

100121113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7781.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 100121113113 its reverse (311311121001), we get a palindrome (411432234114).

The spelling of 100121113113 in words is "one hundred billion, one hundred twenty-one million, one hundred thirteen thousand, one hundred thirteen".