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10012420131 = 371992395889
BaseRepresentation
bin10010101001100100…
…10110100000100011
3221211210010122100020
421110302112200203
5131001134421011
64333304524523
7503055111150
oct112462264043
927753118306
1010012420131
11427882848a
121b35180743
13c3744876c
146ada77227
153d9013006
hex254c96823

10012420131 has 16 divisors (see below), whose sum is σ = 15333696000. Its totient is φ = 5692629888.

The previous prime is 10012420073. The next prime is 10012420133. The reversal of 10012420131 is 13102421001.

10012420131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10012420131 - 210 = 10012419107 is a prime.

It is a super-2 number, since 2×100124201312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10012420131.

It is not an unprimeable number, because it can be changed into a prime (10012420133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1193766 + ... + 1202123.

It is an arithmetic number, because the mean of its divisors is an integer number (958356000).

Almost surely, 210012420131 is an apocalyptic number.

10012420131 is a deficient number, since it is larger than the sum of its proper divisors (5321275869).

10012420131 is a wasteful number, since it uses less digits than its factorization.

10012420131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2396098.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 10012420131 its reverse (13102421001), we get a palindrome (23114841132).

The spelling of 10012420131 in words is "ten billion, twelve million, four hundred twenty thousand, one hundred thirty-one".

Divisors: 1 3 7 21 199 597 1393 4179 2395889 7187667 16771223 50313669 476781911 1430345733 3337473377 10012420131