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100244320131 = 3198009219587
BaseRepresentation
bin101110101011100000…
…1101110111110000011
3100120202012101002110110
41131113001232332003
53120300021221011
6114015051402403
710146101443044
oct1352701567603
9316665332413
10100244320131
113957133a46a
1217517753403
1395b7313a77
144bcd69c8cb
15291a8eaba6
hex175706ef83

100244320131 has 16 divisors (see below), whose sum is σ = 140711990400. Its totient is φ = 63304008768.

The previous prime is 100244320129. The next prime is 100244320139. The reversal of 100244320131 is 131023442001.

It is not a de Polignac number, because 100244320131 - 21 = 100244320129 is a prime.

It is a super-2 number, since 2×1002443201312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100244320098 and 100244320107.

It is not an unprimeable number, because it can be changed into a prime (100244320139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 346720 + ... + 566306.

It is an arithmetic number, because the mean of its divisors is an integer number (8794499400).

Almost surely, 2100244320131 is an apocalyptic number.

100244320131 is a deficient number, since it is larger than the sum of its proper divisors (40467670269).

100244320131 is a wasteful number, since it uses less digits than its factorization.

100244320131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 227618.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 100244320131 its reverse (131023442001), we get a palindrome (231267762132).

The spelling of 100244320131 in words is "one hundred billion, two hundred forty-four million, three hundred twenty thousand, one hundred thirty-one".

Divisors: 1 3 19 57 8009 24027 152171 219587 456513 658761 4172153 12516459 1758672283 5276016849 33414773377 100244320131