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10031214441 = 353433145703
BaseRepresentation
bin10010101011110100…
…00010111101101001
3221220002111111021210
421111322002331221
5131020442330231
64335215423333
7503403626103
oct112572027551
927802444253
1010031214441
1142883a4976
121b3b524b49
13c3b2c9161
146b236a573
153da9c6a46
hex255e82f69

10031214441 has 16 divisors (see below), whose sum is σ = 13658875776. Its totient is φ = 6546099456.

The previous prime is 10031214439. The next prime is 10031214443. The reversal of 10031214441 is 14441213001.

It is an interprime number because it is at equal distance from previous prime (10031214439) and next prime (10031214443).

It is not a de Polignac number, because 10031214441 - 21 = 10031214439 is a prime.

It is a super-2 number, since 2×100312144412 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10031214443) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4005 + ... + 141698.

It is an arithmetic number, because the mean of its divisors is an integer number (853679736).

Almost surely, 210031214441 is an apocalyptic number.

It is an amenable number.

10031214441 is a deficient number, since it is larger than the sum of its proper divisors (3627661335).

10031214441 is a wasteful number, since it uses less digits than its factorization.

10031214441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 146192.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 10031214441 its reverse (14441213001), we get a palindrome (24472427442).

The spelling of 10031214441 in words is "ten billion, thirty-one million, two hundred fourteen thousand, four hundred forty-one".

Divisors: 1 3 53 159 433 1299 22949 68847 145703 437109 7722259 23166777 63089399 189268197 3343738147 10031214441