Base | Representation |
---|---|
bin | 11101010000000010110… |
… | …11000110110110100001 |
3 | 10120002012101210111021111 |
4 | 32220001123012312201 |
5 | 112431313313333213 |
6 | 2045413432423321 |
7 | 132416661001060 |
oct | 16500133066641 |
9 | 3502171714244 |
10 | 1005046230433 |
11 | 358268439573 |
12 | 14294bb47b41 |
13 | 73a10892acb |
14 | 369047001d7 |
15 | 1b2247a0a3d |
hex | ea016c6da1 |
1005046230433 has 16 divisors (see below), whose sum is σ = 1185957319680. Its totient is φ = 833481561600.
The previous prime is 1005046230373. The next prime is 1005046230511. The reversal of 1005046230433 is 3340326405001.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1005046230433 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a junction number, because it is equal to n+sod(n) for n = 1005046230395 and 1005046230404.
It is not an unprimeable number, because it can be changed into a prime (1005046234433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 374253 + ... + 1466341.
It is an arithmetic number, because the mean of its divisors is an integer number (74122332480).
Almost surely, 21005046230433 is an apocalyptic number.
It is an amenable number.
1005046230433 is a deficient number, since it is larger than the sum of its proper divisors (180911089247).
1005046230433 is a wasteful number, since it uses less digits than its factorization.
1005046230433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1096368.
The product of its (nonzero) digits is 25920, while the sum is 31.
The spelling of 1005046230433 in words is "one trillion, five billion, forty-six million, two hundred thirty thousand, four hundred thirty-three".
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