Base | Representation |
---|---|
bin | 101111000101101001… |
… | …1001001101001111001 |
3 | 100200000022120100012120 |
4 | 1132023103021221321 |
5 | 3124044023113423 |
6 | 114242100231453 |
7 | 10206610606650 |
oct | 1361323115171 |
9 | 320008510176 |
10 | 101121301113 |
11 | 3998137a238 |
12 | 1772139b589 |
13 | 96c6c0ab21 |
14 | 4c73d46197 |
15 | 296c8cbee3 |
hex | 178b4c9a79 |
101121301113 has 16 divisors (see below), whose sum is σ = 154096788480. Its totient is φ = 57780905616.
The previous prime is 101121301103. The next prime is 101121301121. The reversal of 101121301113 is 311103121101.
It is not a de Polignac number, because 101121301113 - 214 = 101121284729 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101121301092 and 101121301101.
It is not an unprimeable number, because it can be changed into a prime (101121301103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 403858 + ... + 604436.
It is an arithmetic number, because the mean of its divisors is an integer number (9631049280).
Almost surely, 2101121301113 is an apocalyptic number.
It is an amenable number.
101121301113 is a deficient number, since it is larger than the sum of its proper divisors (52975487367).
101121301113 is a wasteful number, since it uses less digits than its factorization.
101121301113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 224596.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 101121301113 its reverse (311103121101), we get a palindrome (412224422214).
The spelling of 101121301113 in words is "one hundred one billion, one hundred twenty-one million, three hundred one thousand, one hundred thirteen".
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