10113500130433 has 32 divisors (see below), whose sum is σ = 11869921935360. Its totient is φ = 8437070341440.

The previous prime is 10113500130413. The next prime is 10113500130467. The reversal of 10113500130433 is 33403100531101.

It is a cyclic number.

It is not a de Polignac number, because 10113500130433 - 2¹³ = 10113500122241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10113500130398 and 10113500130407.

It is not an unprimeable number, because it can be changed into a prime (10113500130413) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 202882210 + ... + 202932052.

It is an arithmetic number, because the mean of its divisors is an integer number (370935060480).

Almost surely, 2^{10113500130433} is an apocalyptic number.

It is an amenable number.

10113500130433 is a deficient number, since it is larger than the sum of its proper divisors (1756421804927).

10113500130433 is a wasteful number, since it uses less digits than its factorization.

10113500130433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53317.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 10113500130433 its reverse (33403100531101), we get a palindrome (43516600661534).

The spelling of 10113500130433 in words is "ten trillion, one hundred thirteen billion, five hundred million, one hundred thirty thousand, four hundred thirty-three".