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101141343331 = 7257242323203
BaseRepresentation
bin101111000110001111…
…1100110110001100011
3100200001201021120221221
41132030133212301203
53124114140441311
6114244053555511
710210243143040
oct1361437466143
9320051246857
10101141343331
1139991719256
1217728045b97
1396cb107522
144c768821c7
15296e53a671
hex178c7e6c63

101141343331 has 16 divisors (see below), whose sum is σ = 116092767744. Its totient is φ = 86315894784.

The previous prime is 101141343301. The next prime is 101141343367. The reversal of 101141343331 is 133343141101.

It is not a de Polignac number, because 101141343331 - 221 = 101139246179 is a prime.

It is a super-2 number, since 2×1011413433312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101141343296 and 101141343305.

It is not an unprimeable number, because it can be changed into a prime (101141343301) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4347376 + ... + 4370578.

It is an arithmetic number, because the mean of its divisors is an integer number (7255797984).

Almost surely, 2101141343331 is an apocalyptic number.

101141343331 is a deficient number, since it is larger than the sum of its proper divisors (14951424413).

101141343331 is a wasteful number, since it uses less digits than its factorization.

101141343331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25890.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 101141343331 its reverse (133343141101), we get a palindrome (234484484432).

The spelling of 101141343331 in words is "one hundred one billion, one hundred forty-one million, three hundred forty-three thousand, three hundred thirty-one".

Divisors: 1 7 257 1799 2423 16961 23203 162421 622711 4358977 5963171 41742197 56220869 393546083 14448763333 101141343331