101220400113 has 16 divisors (see below), whose sum is σ = 154426692480. Its totient is φ = 57770447616.

The previous prime is 101220400109. The next prime is 101220400117. The reversal of 101220400113 is 311004022101.

It is an interprime number because it is at equal distance from previous prime (101220400109) and next prime (101220400117).

It is not a de Polignac number, because 101220400113 - 2² = 101220400109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101220400092 and 101220400101.

It is not an unprimeable number, because it can be changed into a prime (101220400117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2889720 + ... + 2924537.

It is an arithmetic number, because the mean of its divisors is an integer number (9651668280).

Almost surely, 2^101220400113 is an apocalyptic number.

It is an amenable number.

101220400113 is a deficient number, since it is larger than the sum of its proper divisors (53206292367).

101220400113 is an equidigital number, since it uses as much as digits as its factorization.

101220400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5815096.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 101220400113 its reverse (311004022101), we get a palindrome (412224422214).

The spelling of 101220400113 in words is "one hundred one billion, two hundred twenty million, four hundred thousand, one hundred thirteen".