Base | Representation |
---|---|
bin | 1001001101001100001011… |
… | …1011110100110100100011 |
3 | 1022211200012110022211221220 |
4 | 2103103002323310310203 |
5 | 2311320243113142011 |
6 | 33310025230350123 |
7 | 2063206612246302 |
oct | 223230273646443 |
9 | 38750173284856 |
10 | 10122213412131 |
11 | 3252896649467 |
12 | 117590495b343 |
13 | 58569ca8bbc2 |
14 | 26dcbc404439 |
15 | 12847e3b4506 |
hex | 934c2ef4d23 |
10122213412131 has 16 divisors (see below), whose sum is σ = 13862736710400. Its totient is φ = 6564960607968.
The previous prime is 10122213412127. The next prime is 10122213412243. The reversal of 10122213412131 is 13121431222101.
10122213412131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10122213412131 - 22 = 10122213412127 is a prime.
It is a super-2 number, since 2×101222134121312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (10122213412111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4635271 + ... + 6459888.
It is an arithmetic number, because the mean of its divisors is an integer number (866421044400).
Almost surely, 210122213412131 is an apocalyptic number.
10122213412131 is a deficient number, since it is larger than the sum of its proper divisors (3740523298269).
10122213412131 is a wasteful number, since it uses less digits than its factorization.
10122213412131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11103418.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 10122213412131 its reverse (13121431222101), we get a palindrome (23243644634232).
The spelling of 10122213412131 in words is "ten trillion, one hundred twenty-two billion, two hundred thirteen million, four hundred twelve thousand, one hundred thirty-one".
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