Base | Representation |
---|---|
bin | 1001010010010011001110… |
… | …0010110010111011100001 |
3 | 1100011001210121002022021020 |
4 | 2110210303202302323201 |
5 | 2314240041004201423 |
6 | 33414224333120053 |
7 | 2102435240154525 |
oct | 224446342627341 |
9 | 40131717068236 |
10 | 10210002022113 |
11 | 3287045a704a3 |
12 | 118a925029029 |
13 | 590a506c237a |
14 | 27424973bd85 |
15 | 12a8bb5244e3 |
hex | 949338b2ee1 |
10210002022113 has 32 divisors (see below), whose sum is σ = 13994410450944. Its totient is φ = 6617605018752.
The previous prime is 10210002022067. The next prime is 10210002022133. The reversal of 10210002022113 is 31122020001201.
It is not a de Polignac number, because 10210002022113 - 221 = 10209999924961 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10210002022092 and 10210002022101.
It is not an unprimeable number, because it can be changed into a prime (10210002022133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 237680245 + ... + 237723197.
It is an arithmetic number, because the mean of its divisors is an integer number (437325326592).
Almost surely, 210210002022113 is an apocalyptic number.
It is an amenable number.
10210002022113 is a deficient number, since it is larger than the sum of its proper divisors (3784408428831).
10210002022113 is a wasteful number, since it uses less digits than its factorization.
10210002022113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51485.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 10210002022113 its reverse (31122020001201), we get a palindrome (41332022023314).
The spelling of 10210002022113 in words is "ten trillion, two hundred ten billion, two million, twenty-two thousand, one hundred thirteen".
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