Base | Representation |
---|---|
bin | 10011000001011011… |
… | …10010111101101001 |
3 | 222100201201102102011 |
4 | 21200231302331221 |
5 | 131403403140203 |
6 | 4405214235521 |
7 | 511035156460 |
oct | 114055627551 |
9 | 28321642364 |
10 | 10212552553 |
11 | 43707a0985 |
12 | 1b901b5ba1 |
13 | c69a4b108 |
14 | 6cc4919d7 |
15 | 3eb89676d |
hex | 260b72f69 |
10212552553 has 16 divisors (see below), whose sum is σ = 11744046976. Its totient is φ = 8699322240.
The previous prime is 10212552541. The next prime is 10212552569. The reversal of 10212552553 is 35525521201.
10212552553 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10212552553 - 225 = 10178998121 is a prime.
It is a super-3 number, since 3×102125525533 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10212550553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1077925 + ... + 1087357.
It is an arithmetic number, because the mean of its divisors is an integer number (734002936).
Almost surely, 210212552553 is an apocalyptic number.
It is an amenable number.
10212552553 is a deficient number, since it is larger than the sum of its proper divisors (1531494423).
10212552553 is an equidigital number, since it uses as much as digits as its factorization.
10212552553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10384.
The product of its (nonzero) digits is 15000, while the sum is 31.
The spelling of 10212552553 in words is "ten billion, two hundred twelve million, five hundred fifty-two thousand, five hundred fifty-three".
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