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10344023433 = 34733174221
BaseRepresentation
bin10011010001000110…
…10100010110001001
3222200220002211120000
421220203110112021
5132141032222213
64430232153213
7514222514502
oct115043242611
928626084500
1010344023433
114428a279a7
122008238809
13c8b060233
14701b15ba9
154081b5c73
hex2688d4589

10344023433 has 20 divisors (see below), whose sum is σ = 15473352708. Its totient is φ = 6886568160.

The previous prime is 10344023413. The next prime is 10344023471. The reversal of 10344023433 is 33432044301.

It can be written as a sum of positive squares in 2 ways, for example, as 5091107904 + 5252915529 = 71352^2 + 72477^2 .

It is not a de Polignac number, because 10344023433 - 224 = 10327246217 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 10344023397 and 10344023406.

It is not an unprimeable number, because it can be changed into a prime (10344023413) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 27738 + ... + 146483.

Almost surely, 210344023433 is an apocalyptic number.

It is an amenable number.

10344023433 is a deficient number, since it is larger than the sum of its proper divisors (5129329275).

10344023433 is an equidigital number, since it uses as much as digits as its factorization.

10344023433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 174966 (or 174957 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 27.

Adding to 10344023433 its reverse (33432044301), we get a palindrome (43776067734).

The spelling of 10344023433 in words is "ten billion, three hundred forty-four million, twenty-three thousand, four hundred thirty-three".

Divisors: 1 3 9 27 81 733 2199 6597 19791 59373 174221 522663 1567989 4703967 14111901 127703993 383111979 1149335937 3448007811 10344023433