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10552017 = 374710691
BaseRepresentation
bin101000010000…
…001011010001
3201212002122110
4220100023101
510200131032
61014055533
7155455620
oct50201321
921762573
1010552017
115a57983
12364a5a9
132255bc8
1415896b7
15dd67cc
hexa102d1

10552017 has 16 divisors (see below), whose sum is σ = 16422912. Its totient is φ = 5900880.

The previous prime is 10552013. The next prime is 10552021. The reversal of 10552017 is 71025501.

It is an interprime number because it is at equal distance from previous prime (10552013) and next prime (10552021).

It is not a de Polignac number, because 10552017 - 22 = 10552013 is a prime.

It is a super-2 number, since 2×105520172 = 222690125536578, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 10551984 and 10552002.

It is not an unprimeable number, because it can be changed into a prime (10552013) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4359 + ... + 6332.

It is an arithmetic number, because the mean of its divisors is an integer number (1026432).

Almost surely, 210552017 is an apocalyptic number.

It is an amenable number.

10552017 is a deficient number, since it is larger than the sum of its proper divisors (5870895).

10552017 is a wasteful number, since it uses less digits than its factorization.

10552017 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10748.

The product of its (nonzero) digits is 350, while the sum is 21.

The square root of 10552017 is about 3248.3868304129. The cubic root of 10552017 is about 219.3369638035.

Adding to 10552017 its reverse (71025501), we get a palindrome (81577518).

The spelling of 10552017 in words is "ten million, five hundred fifty-two thousand, seventeen".

Divisors: 1 3 7 21 47 141 329 987 10691 32073 74837 224511 502477 1507431 3517339 10552017