Base | Representation |
---|---|
bin | 10100011111010100… |
… | …11110111101010011 |
3 | 1001101121211201212120 |
4 | 22033222132331103 |
5 | 140012023311311 |
6 | 5015312425323 |
7 | 536411161542 |
oct | 121752367523 |
9 | 31347751776 |
10 | 11000213331 |
11 | 47353740a8 |
12 | 216bb48243 |
13 | 1063ca0793 |
14 | 764d28159 |
15 | 445ad2706 |
hex | 28fa9ef53 |
11000213331 has 16 divisors (see below), whose sum is σ = 15181983744. Its totient is φ = 7079081184.
The previous prime is 11000213311. The next prime is 11000213339. The reversal of 11000213331 is 13331200011.
It is not a de Polignac number, because 11000213331 - 25 = 11000213299 is a prime.
It is a super-2 number, since 2×110002133312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11000213331.
It is not an unprimeable number, because it can be changed into a prime (11000213339) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 376065 + ... + 404258.
It is an arithmetic number, because the mean of its divisors is an integer number (948873984).
Almost surely, 211000213331 is an apocalyptic number.
11000213331 is a deficient number, since it is larger than the sum of its proper divisors (4181770413).
11000213331 is a wasteful number, since it uses less digits than its factorization.
11000213331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 780490.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11000213331 its reverse (13331200011), we get a palindrome (24331413342).
The spelling of 11000213331 in words is "eleven billion, two hundred thirteen thousand, three hundred thirty-one".
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