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1100112022131 = 34931589712611
BaseRepresentation
bin10000000000100011110…
…010010100101001110011
310220011120200212002012120
4100000203302110221303
5121011012134202011
62201215014325323
7142323541620453
oct20004362245163
93804520762176
101100112022131
11394611613971
12159261359843
137c98106ab65
143b362307d63
151d93a72ca06
hex10023c94a73

1100112022131 has 16 divisors (see below), whose sum is σ = 1467478643328. Its totient is φ = 733076801600.

The previous prime is 1100112022091. The next prime is 1100112022153. The reversal of 1100112022131 is 1312202110011.

It is a cyclic number.

It is not a de Polignac number, because 1100112022131 - 217 = 1100111891059 is a prime.

It is a super-2 number, since 2×11001120221312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1100112022131.

It is not an unprimeable number, because it can be changed into a prime (1100112722131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 87228016 + ... + 87240626.

It is an arithmetic number, because the mean of its divisors is an integer number (91717415208).

Almost surely, 21100112022131 is an apocalyptic number.

1100112022131 is a deficient number, since it is larger than the sum of its proper divisors (367366621197).

1100112022131 is a wasteful number, since it uses less digits than its factorization.

1100112022131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23442.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1100112022131 its reverse (1312202110011), we get a palindrome (2412314132142).

The spelling of 1100112022131 in words is "one trillion, one hundred billion, one hundred twelve million, twenty-two thousand, one hundred thirty-one".

Divisors: 1 3 4931 5897 12611 14793 17691 37833 29078107 62184841 74367067 87234321 186554523 223101201 366704007377 1100112022131