Base | Representation |
---|---|
bin | 11001000000111001101101… |
… | …000000101111110111001011 |
3 | 112102112011002120110110001220 |
4 | 121000321231000233313023 |
5 | 103404423333013413311 |
6 | 1025551155153213123 |
7 | 32113120462250322 |
oct | 3100715500576713 |
9 | 472464076413056 |
10 | 110013121232331 |
11 | 32065336999259 |
12 | 104093438611a3 |
13 | 495026780bc65 |
14 | 1d249408270b9 |
15 | caba61610206 |
hex | 640e6d02fdcb |
110013121232331 has 16 divisors (see below), whose sum is σ = 147689715808800. Its totient is φ = 72839444384000.
The previous prime is 110013121232309. The next prime is 110013121232359. The reversal of 110013121232331 is 133232121310011.
It is a cyclic number.
It is not a de Polignac number, because 110013121232331 - 217 = 110013121101259 is a prime.
It is a super-2 number, since 2×1100131212323312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (110013121233331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14447640 + ... + 20706533.
It is an arithmetic number, because the mean of its divisors is an integer number (9230607238050).
Almost surely, 2110013121232331 is an apocalyptic number.
110013121232331 is a deficient number, since it is larger than the sum of its proper divisors (37676594576469).
110013121232331 is a wasteful number, since it uses less digits than its factorization.
110013121232331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35161326.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 110013121232331 its reverse (133232121310011), we get a palindrome (243245242542342).
The spelling of 110013121232331 in words is "one hundred ten trillion, thirteen billion, one hundred twenty-one million, two hundred thirty-two thousand, three hundred thirty-one".
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