Base | Representation |
---|---|
bin | 11001000001010100100111… |
… | …100001100011111001000011 |
3 | 112102121220200120222010000220 |
4 | 121001110213201203321003 |
5 | 103410412024132400003 |
6 | 1030012334534314123 |
7 | 32115162562363353 |
oct | 3101244741437103 |
9 | 472556616863026 |
10 | 110042020200003 |
11 | 32076616682411 |
12 | 10412a69ab8943 |
13 | 4952bc1a51528 |
14 | 1d260c2944b63 |
15 | cac6a374c353 |
hex | 641527863e43 |
110042020200003 has 16 divisors (see below), whose sum is σ = 148622923438080. Its totient is φ = 72411769138176.
The previous prime is 110042020200001. The next prime is 110042020200029. The reversal of 110042020200003 is 300002020240011.
It is not a de Polignac number, because 110042020200003 - 21 = 110042020200001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (110042020200001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 66336075 + ... + 67974692.
It is an arithmetic number, because the mean of its divisors is an integer number (9288932714880).
Almost surely, 2110042020200003 is an apocalyptic number.
110042020200003 is a deficient number, since it is larger than the sum of its proper divisors (38580903238077).
110042020200003 is a wasteful number, since it uses less digits than its factorization.
110042020200003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 134314306.
The product of its (nonzero) digits is 96, while the sum is 15.
Adding to 110042020200003 its reverse (300002020240011), we get a palindrome (410044040440014).
The spelling of 110042020200003 in words is "one hundred ten trillion, forty-two billion, twenty million, two hundred thousand, three".
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