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11012221202001 = 319202499541057
BaseRepresentation
bin1010000000111111101110…
…0010000110111001010001
31102222202110122000001202120
42200033323202012321101
52420411012111431001
635230540010204453
72214415051531005
oct240177342067121
942882418001676
1011012221202001
113566290864958
12129a2aa723729
1361b5a9357426
142a0dcc6d4705
151416be571236
hexa03fb886e51

11012221202001 has 16 divisors (see below), whose sum is σ = 15456513960000. Its totient is φ = 6954742867968.

The previous prime is 11012221201991. The next prime is 11012221202029. The reversal of 11012221202001 is 10020212221011.

It is not a de Polignac number, because 11012221202001 - 221 = 11012219104849 is a prime.

It is a super-4 number, since 4×110122212020014 (a number of 53 digits) contains 4444 as substring.

It is not an unprimeable number, because it can be changed into a prime (11012221201001) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3616336 + ... + 5924721.

It is an arithmetic number, because the mean of its divisors is an integer number (966032122500).

Almost surely, 211012221202001 is an apocalyptic number.

It is an amenable number.

11012221202001 is a deficient number, since it is larger than the sum of its proper divisors (4444292757999).

11012221202001 is a wasteful number, since it uses less digits than its factorization.

11012221202001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9561328.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 11012221202001 its reverse (10020212221011), we get a palindrome (21032433423012).

The spelling of 11012221202001 in words is "eleven trillion, twelve billion, two hundred twenty-one million, two hundred two thousand, one".

Divisors: 1 3 19 57 20249 60747 384731 1154193 9541057 28623171 181280083 543840249 193196863193 579590589579 3670740400667 11012221202001