Base | Representation |
---|---|
bin | 10100100011010001… |
… | …10111000111100001 |
3 | 1001110221011212110100 |
4 | 22101220313013201 |
5 | 140044013424213 |
6 | 5022454453013 |
7 | 540262602051 |
oct | 122150670741 |
9 | 31427155410 |
10 | 11033342433 |
11 | 4752041523 |
12 | 217b064169 |
13 | 106aaccab9 |
14 | 7694ad561 |
15 | 448978773 |
hex | 291a371e1 |
11033342433 has 48 divisors (see below), whose sum is σ = 16509664080. Its totient is φ = 7095859200.
The previous prime is 11033342413. The next prime is 11033342459. The reversal of 11033342433 is 33424333011.
It can be written as a sum of positive squares in 8 ways, for example, as 7679542689 + 3353799744 = 87633^2 + 57912^2 .
It is not a de Polignac number, because 11033342433 - 213 = 11033334241 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11033342397 and 11033342406.
It is not an unprimeable number, because it can be changed into a prime (11033342413) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 15561483 + ... + 15562191.
It is an arithmetic number, because the mean of its divisors is an integer number (343951335).
Almost surely, 211033342433 is an apocalyptic number.
It is an amenable number.
11033342433 is a deficient number, since it is larger than the sum of its proper divisors (5476321647).
11033342433 is a wasteful number, since it uses less digits than its factorization.
11033342433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1170 (or 1167 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 27.
Adding to 11033342433 its reverse (33424333011), we get a palindrome (44457675444).
The spelling of 11033342433 in words is "eleven billion, thirty-three million, three hundred forty-two thousand, four hundred thirty-three".
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