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1104040201323 = 31931162280149
BaseRepresentation
bin10000000100001101111…
…011001000110001101011
310220112201110102021000210
4100010031323020301223
5121042033242420243
62203104501032203
7142523100605103
oct20041573106153
93815643367023
101104040201323
11396247a03054
12159b789b5663
1380158b34047
143b615cc4203
151daba517933
hex1010dec8c6b

1104040201323 has 16 divisors (see below), whose sum is σ = 1554512544000. Its totient is φ = 695046451680.

The previous prime is 1104040201261. The next prime is 1104040201373. The reversal of 1104040201323 is 3231020404011.

It is not a de Polignac number, because 1104040201323 - 28 = 1104040201067 is a prime.

It is a super-2 number, since 2×11040402013232 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1104040201323.

It is not an unprimeable number, because it can be changed into a prime (1104040201373) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31122348 + ... + 31157801.

It is an arithmetic number, because the mean of its divisors is an integer number (97157034000).

Almost surely, 21104040201323 is an apocalyptic number.

1104040201323 is a deficient number, since it is larger than the sum of its proper divisors (450472342677).

1104040201323 is a wasteful number, since it uses less digits than its factorization.

1104040201323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62280482.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1104040201323 its reverse (3231020404011), we get a palindrome (4335060605334).

The spelling of 1104040201323 in words is "one trillion, one hundred four billion, forty million, two hundred one thousand, three hundred twenty-three".

Divisors: 1 3 19 57 311 933 5909 17727 62280149 186840447 1183322831 3549968493 19369126339 58107379017 368013400441 1104040201323