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110483548113 = 3315212280221
BaseRepresentation
bin110011011100101010…
…1010010011111010001
3101120011210021202200110
41212321111102133101
53302232242014423
6122431101511533
710660612443501
oct1467125223721
9346153252613
10110483548113
114294609aa54
12194b48725a9
13a559741853
1454c14d5a01
152d197b1193
hex19b95527d1

110483548113 has 16 divisors (see below), whose sum is σ = 152355313152. Its totient is φ = 71142864000.

The previous prime is 110483548111. The next prime is 110483548139. The reversal of 110483548113 is 311845384011.

It is not a de Polignac number, because 110483548113 - 21 = 110483548111 is a prime.

It is a super-2 number, since 2×1104835481132 (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (110483548111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1091658 + ... + 1188563.

It is an arithmetic number, because the mean of its divisors is an integer number (9522207072).

Almost surely, 2110483548113 is an apocalyptic number.

It is an amenable number.

110483548113 is a deficient number, since it is larger than the sum of its proper divisors (41871765039).

110483548113 is a wasteful number, since it uses less digits than its factorization.

110483548113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2280776.

The product of its (nonzero) digits is 46080, while the sum is 39.

The spelling of 110483548113 in words is "one hundred ten billion, four hundred eighty-three million, five hundred forty-eight thousand, one hundred thirteen".

Divisors: 1 3 31 93 521 1563 16151 48453 2280221 6840663 70686851 212060553 1187995141 3563985423 36827849371 110483548113