111003222433041 has 16 divisors (see below), whose sum is σ = 166765404597120. Its totient is φ = 72959864508720.

The previous prime is 111003222433009. The next prime is 111003222433073. The reversal of 111003222433041 is 140334222300111.

111003222433041 is a `hidden beast` number, since 1 + 1 + 1 + 0 + 0 + 3 + 222 + 433 + 0 + 4 + 1 = 666.

It is an interprime number because it is at equal distance from previous prime (111003222433009) and next prime (111003222433073).

It is not a de Polignac number, because 111003222433041 - 2⁵ = 111003222433009 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 111003222432996 and 111003222433014.

It is not an unprimeable number, because it can be changed into a prime (111003222453041) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28952325270 + ... + 28952329103.

It is an arithmetic number, because the mean of its divisors is an integer number (10422837787320).

Almost surely, 2^{111003222433041} is an apocalyptic number.

It is an amenable number.

111003222433041 is a deficient number, since it is larger than the sum of its proper divisors (55762182164079).

111003222433041 is an equidigital number, since it uses as much as digits as its factorization.

111003222433041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57904654453 (or 57904654447 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 111003222433041 its reverse (140334222300111), we get a palindrome (251337444733152).

The spelling of 111003222433041 in words is "one hundred eleven trillion, three billion, two hundred twenty-two million, four hundred thirty-three thousand, forty-one".