Base | Representation |
---|---|
bin | 10000001010000100111… |
… | …001001000100011010001 |
3 | 10221010221212220122201110 |
4 | 100022010321020203101 |
5 | 121142424232211423 |
6 | 2210025025323533 |
7 | 143135016621150 |
oct | 20120471104321 |
9 | 3833855818643 |
10 | 1110331132113 |
11 | 398985a83505 |
12 | 15b2337965a9 |
13 | 8091c2738b8 |
14 | 3ba515c5597 |
15 | 1dd3796c193 |
hex | 10284e488d1 |
1110331132113 has 32 divisors (see below), whose sum is σ = 1694786503680. Its totient is φ = 633405764160.
The previous prime is 1110331132091. The next prime is 1110331132123. The reversal of 1110331132113 is 3112311330111.
It is not a de Polignac number, because 1110331132113 - 25 = 1110331132081 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 1110331132113.
It is not an unprimeable number, because it can be changed into a prime (1110331132123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 34478023 + ... + 34510211.
It is an arithmetic number, because the mean of its divisors is an integer number (52962078240).
Almost surely, 21110331132113 is an apocalyptic number.
It is an amenable number.
1110331132113 is a deficient number, since it is larger than the sum of its proper divisors (584455371567).
1110331132113 is a wasteful number, since it uses less digits than its factorization.
1110331132113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34917.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 1110331132113 its reverse (3112311330111), we get a palindrome (4222642462224).
The spelling of 1110331132113 in words is "one trillion, one hundred ten billion, three hundred thirty-one million, one hundred thirty-two thousand, one hundred thirteen".
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