Base | Representation |
---|---|
bin | 11001010010011000011001… |
… | …011101100100011011010010 |
3 | 112120202222120111200201011011 |
4 | 121102120121131210123102 |
5 | 104034113401422010102 |
6 | 1032311052052441134 |
7 | 32265653200243366 |
oct | 3122303135443322 |
9 | 476688514621134 |
10 | 111214310344402 |
11 | 324887a69248a1 |
12 | 105820b36191aa |
13 | 4a09606578375 |
14 | 1d66b30c492a6 |
15 | ccce158d52d7 |
hex | 6526197646d2 |
111214310344402 has 32 divisors (see below), whose sum is σ = 170798023851840. Its totient is φ = 54295089376320.
The previous prime is 111214310344399. The next prime is 111214310344421. The reversal of 111214310344402 is 204443013412111.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 132753613 + ... + 133588735.
It is an arithmetic number, because the mean of its divisors is an integer number (5337438245370).
Almost surely, 2111214310344402 is an apocalyptic number.
111214310344402 is a deficient number, since it is larger than the sum of its proper divisors (59583713507438).
111214310344402 is a wasteful number, since it uses less digits than its factorization.
111214310344402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 843178.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 111214310344402 its reverse (204443013412111), we get a palindrome (315657323756513).
The spelling of 111214310344402 in words is "one hundred eleven trillion, two hundred fourteen billion, three hundred ten million, three hundred forty-four thousand, four hundred two".
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