Base | Representation |
---|---|
bin | 1010000111100001010111… |
… | …1011111100001101110010 |
3 | 1110101110211220202022212020 |
4 | 2201320111323330031302 |
5 | 2424230113313100224 |
6 | 35354240450212310 |
7 | 2225464231103610 |
oct | 241702573741562 |
9 | 43343756668766 |
10 | 11124333331314 |
11 | 35a9892177a85 |
12 | 12b7b78884096 |
13 | 6290352cac98 |
14 | 2a65c62006b0 |
15 | 144581cc9c79 |
hex | a1e15efc372 |
11124333331314 has 64 divisors (see below), whose sum is σ = 25750134681600. Its totient is φ = 3137998900608.
The previous prime is 11124333331289. The next prime is 11124333331339. The reversal of 11124333331314 is 41313333342111.
It is an interprime number because it is at equal distance from previous prime (11124333331289) and next prime (11124333331339).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 82514349 + ... + 82649055.
It is an arithmetic number, because the mean of its divisors is an integer number (402345854400).
Almost surely, 211124333331314 is an apocalyptic number.
11124333331314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
11124333331314 is an abundant number, since it is smaller than the sum of its proper divisors (14625801350286).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11124333331314 is a wasteful number, since it uses less digits than its factorization.
11124333331314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159687.
The product of its digits is 23328, while the sum is 33.
Adding to 11124333331314 its reverse (41313333342111), we get a palindrome (52437666673425).
The spelling of 11124333331314 in words is "eleven trillion, one hundred twenty-four billion, three hundred thirty-three million, three hundred thirty-one thousand, three hundred fourteen".
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