Base | Representation |
---|---|
bin | 10000001100000010001… |
… | …101001111001011001001 |
3 | 10221100101101222202112020 |
4 | 100030002031033023021 |
5 | 121211230442212441 |
6 | 2211013411435053 |
7 | 143241066123321 |
oct | 20140215171311 |
9 | 3840341882466 |
10 | 1112433554121 |
11 | 39986481625a |
12 | 15b71b8b5a89 |
13 | 80b959cbca6 |
14 | 3bbb0902281 |
15 | 1de0c311e66 |
hex | 1030234f2c9 |
1112433554121 has 16 divisors (see below), whose sum is σ = 1524941166144. Its totient is φ = 720816490944.
The previous prime is 1112433554087. The next prime is 1112433554131. The reversal of 1112433554121 is 1214553342111.
It is not a de Polignac number, because 1112433554121 - 213 = 1112433545929 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1112433554131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5186290 + ... + 5396523.
It is an arithmetic number, because the mean of its divisors is an integer number (95308822884).
Almost surely, 21112433554121 is an apocalyptic number.
It is an amenable number.
1112433554121 is a deficient number, since it is larger than the sum of its proper divisors (412507612023).
1112433554121 is a wasteful number, since it uses less digits than its factorization.
1112433554121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10583800.
The product of its digits is 14400, while the sum is 33.
Adding to 1112433554121 its reverse (1214553342111), we get a palindrome (2326986896232).
The spelling of 1112433554121 in words is "one trillion, one hundred twelve billion, four hundred thirty-three million, five hundred fifty-four thousand, one hundred twenty-one".
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