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11130003210312 = 23327193746168141
BaseRepresentation
bin1010000111110110011111…
…1000110100000001001000
31110102000111001122000122200
42201331213320310001020
52424323221310212222
635401015231320200
72226054566221230
oct241754770640110
943360431560580
1011130003210312
113601231720a98
1212b909b680060
13629729b80b7c
142a69a3238cc0
151447b4953eac
hexa1f67e34048

11130003210312 has 384 divisors, whose sum is σ = 37324589702400. Its totient is φ = 2924808652800.

The previous prime is 11130003210299. The next prime is 11130003210341. The reversal of 11130003210312 is 21301230003111.

11130003210312 is a `hidden beast` number, since 1 + 1 + 1 + 30 + 0 + 0 + 321 + 0 + 312 = 666.

It is a super-2 number, since 2×111300032103122 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 163303762 + ... + 163371902.

It is an arithmetic number, because the mean of its divisors is an integer number (97199452350).

Almost surely, 211130003210312 is an apocalyptic number.

11130003210312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11130003210312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18662294851200).

11130003210312 is an abundant number, since it is smaller than the sum of its proper divisors (26194586492088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11130003210312 is a wasteful number, since it uses less digits than its factorization.

11130003210312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68677 (or 68670 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 11130003210312 its reverse (21301230003111), we get a palindrome (32431233213423).

The spelling of 11130003210312 in words is "eleven trillion, one hundred thirty billion, three million, two hundred ten thousand, three hundred twelve".