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111312311133132 = 223431371549319333
BaseRepresentation
bin11001010011110011101010…
…110000111010001111001100
3112121010100112100110121010000
4121103303222300322033030
5104042220103122230012
61032424100401444300
732306022560223534
oct3123635260721714
9477110470417100
10111312311133132
113251631680197a
12105990a3940690
134a15923b28755
141d6b78a5784c4
15cd074e365ddc
hex653ceac3a3cc

111312311133132 has 240 divisors, whose sum is σ = 308533446952192. Its totient is φ = 34932670364160.

The previous prime is 111312311133131. The next prime is 111312311133139. The reversal of 111312311133132 is 231331113213111.

111312311133132 is a `hidden beast` number, since 1 + 1 + 1 + 3 + 1 + 231 + 113 + 313 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 111312311133096 and 111312311133105.

It is not an unprimeable number, because it can be changed into a prime (111312311133131) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 5757622938 + ... + 5757642270.

Almost surely, 2111312311133132 is an apocalyptic number.

111312311133132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111312311133132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (154266723476096).

111312311133132 is an abundant number, since it is smaller than the sum of its proper divisors (197221135819060).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111312311133132 is a wasteful number, since it uses less digits than its factorization.

111312311133132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34910 (or 34899 counting only the distinct ones).

The product of its digits is 972, while the sum is 27.

Adding to 111312311133132 its reverse (231331113213111), we get a palindrome (342643424346243).

The spelling of 111312311133132 in words is "one hundred eleven trillion, three hundred twelve billion, three hundred eleven million, one hundred thirty-three thousand, one hundred thirty-two".