Base | Representation |
---|---|
bin | 1010001100110000110000… |
… | …0001011110111111110001 |
3 | 1110201002020010022021212020 |
4 | 2203030030001132333301 |
5 | 2432214002444404203 |
6 | 35503450110422053 |
7 | 2235132220323201 |
oct | 243141401367761 |
9 | 43632203267766 |
10 | 11214361325553 |
11 | 3633a90679601 |
12 | 1311502b01929 |
13 | 634681b722a9 |
14 | 2aaac6b08401 |
15 | 146aa0836153 |
hex | a330c05eff1 |
11214361325553 has 16 divisors (see below), whose sum is σ = 15059449859136. Its totient is φ = 7422831074880.
The previous prime is 11214361325521. The next prime is 11214361325567. The reversal of 11214361325553 is 35552316341211.
11214361325553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11214361325553 - 25 = 11214361325521 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11214361325353) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8674618 + ... + 9883203.
It is an arithmetic number, because the mean of its divisors is an integer number (941215616196).
Almost surely, 211214361325553 is an apocalyptic number.
It is an amenable number.
11214361325553 is a deficient number, since it is larger than the sum of its proper divisors (3845088533583).
11214361325553 is a wasteful number, since it uses less digits than its factorization.
11214361325553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18559264.
The product of its digits is 324000, while the sum is 42.
Adding to 11214361325553 its reverse (35552316341211), we get a palindrome (46766677666764).
The spelling of 11214361325553 in words is "eleven trillion, two hundred fourteen billion, three hundred sixty-one million, three hundred twenty-five thousand, five hundred fifty-three".
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