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11304320015234 = 2591811645132173
BaseRepresentation
bin1010010001111111110111…
…1110101001101110000010
31111000200102111110012212202
42210133331332221232002
52440202221410441414
640013044413353202
72244465405503411
oct244377576515602
944020374405782
1011304320015234
113669153a44634
121326a29a98802
1363ccba25c49c
142b11bc331478
151490b82529de
hexa47fdfa9b82

11304320015234 has 32 divisors (see below), whose sum is σ = 17340740988480. Its totient is φ = 5525154936000.

The previous prime is 11304320015207. The next prime is 11304320015279. The reversal of 11304320015234 is 43251002340311.

It is a super-3 number, since 3×113043200152343 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11304320015197 and 11304320015206.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 351344372 + ... + 351376544.

It is an arithmetic number, because the mean of its divisors is an integer number (541898155890).

Almost surely, 211304320015234 is an apocalyptic number.

11304320015234 is a deficient number, since it is larger than the sum of its proper divisors (6036420973246).

11304320015234 is a wasteful number, since it uses less digits than its factorization.

11304320015234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48866.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 11304320015234 its reverse (43251002340311), we get a palindrome (54555322355545).

The spelling of 11304320015234 in words is "eleven trillion, three hundred four billion, three hundred twenty million, fifteen thousand, two hundred thirty-four".

Divisors: 1 2 59 118 181 362 10679 16451 21358 32173 32902 64346 970609 1898207 1941218 2977631 3796414 5823313 5955262 11646626 175680229 343575467 351360458 529278023 687150934 1058556046 31227403357 62454806714 95799322163 191598644326 5652160007617 11304320015234