Base | Representation |
---|---|
bin | 1010010010011101101100… |
… | …0000000111001111011011 |
3 | 1111001110002020201120220000 |
4 | 2210213123000013033123 |
5 | 2440320114210132311 |
6 | 40020450504104043 |
7 | 2245200625036446 |
oct | 244473300071733 |
9 | 44043066646800 |
10 | 11312323130331 |
11 | 367159054a443 |
12 | 13284a2165023 |
13 | 640994323452 |
14 | 2b173b1aa65d |
15 | 1493d5b66056 |
hex | a49db0073db |
11312323130331 has 10 divisors (see below), whose sum is σ = 16898655540492. Its totient is φ = 7541548753500.
The previous prime is 11312323130321. The next prime is 11312323130399. The reversal of 11312323130331 is 13303132321311.
11312323130331 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 2 + 323 + 1 + 3 + 0 + 331 = 666.
11312323130331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11312323130331 - 215 = 11312323097563 is a prime.
It is a super-2 number, since 2×113123231303312 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 11312323130295 and 11312323130304.
It is not an unprimeable number, because it can be changed into a prime (11312323130321) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 69829155045 + ... + 69829155206.
Almost surely, 211312323130331 is an apocalyptic number.
11312323130331 is a deficient number, since it is larger than the sum of its proper divisors (5586332410161).
11312323130331 is an equidigital number, since it uses as much as digits as its factorization.
11312323130331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139658310263 (or 139658310254 counting only the distinct ones).
The product of its (nonzero) digits is 2916, while the sum is 27.
Adding to 11312323130331 its reverse (13303132321311), we get a palindrome (24615455451642).
The spelling of 11312323130331 in words is "eleven trillion, three hundred twelve billion, three hundred twenty-three million, one hundred thirty thousand, three hundred thirty-one".
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