Base | Representation |
---|---|
bin | 10101000100100111… |
… | …01011100111111011 |
3 | 1002012102102002122020 |
4 | 22202103223213323 |
5 | 141132112044003 |
6 | 5110324525523 |
7 | 550226640021 |
oct | 124223534773 |
9 | 32172362566 |
10 | 11313003003 |
11 | 4885993665 |
12 | 22388508a3 |
13 | 10b3a28b23 |
14 | 7946aa711 |
15 | 4632bad53 |
hex | 2a24eb9fb |
11313003003 has 16 divisors (see below), whose sum is σ = 15274054656. Its totient is φ = 7447076000.
The previous prime is 11313003001. The next prime is 11313003017. The reversal of 11313003003 is 30030031311.
It is a cyclic number.
It is not a de Polignac number, because 11313003003 - 21 = 11313003001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11313003001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 485878 + ... + 508628.
It is an arithmetic number, because the mean of its divisors is an integer number (954628416).
Almost surely, 211313003003 is an apocalyptic number.
11313003003 is a deficient number, since it is larger than the sum of its proper divisors (3961051653).
11313003003 is a wasteful number, since it uses less digits than its factorization.
11313003003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24834.
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 11313003003 its reverse (30030031311), we get a palindrome (41343034314).
The spelling of 11313003003 in words is "eleven billion, three hundred thirteen million, three thousand, three".
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