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11314114433 = 192947436889
BaseRepresentation
bin10101000100101111…
…11010111110000001
31002012111111120020022
422202113322332001
5141132403130213
65110404423225
7550242246236
oct124227727601
932174446208
1011314114433
1148865826a6
1222390a7b15
1310b402798b
147948b978d
1546343a308
hex2a25faf81

11314114433 has 16 divisors (see below), whose sum is σ = 12582432000. Its totient is φ = 10128811392.

The previous prime is 11314114417. The next prime is 11314114447. The reversal of 11314114433 is 33441141311.

It is a cyclic number.

It is not a de Polignac number, because 11314114433 - 24 = 11314114417 is a prime.

It is a super-2 number, since 2×113141144332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11314111433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 192548 + ... + 244341.

It is an arithmetic number, because the mean of its divisors is an integer number (786402000).

Almost surely, 211314114433 is an apocalyptic number.

It is an amenable number.

11314114433 is a deficient number, since it is larger than the sum of its proper divisors (1268317567).

11314114433 is a wasteful number, since it uses less digits than its factorization.

11314114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 436984.

The product of its digits is 1728, while the sum is 26.

Adding to 11314114433 its reverse (33441141311), we get a palindrome (44755255744).

The spelling of 11314114433 in words is "eleven billion, three hundred fourteen million, one hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 19 29 47 551 893 1363 25897 436889 8300891 12669781 20533783 240725839 390141877 595479707 11314114433