Base | Representation |
---|---|
bin | 110100101101101000… |
… | …1011010111110101011 |
3 | 101211012010121100020101 |
4 | 1221123101122332223 |
5 | 3323313303141212 |
6 | 124000434210231 |
7 | 11115132614650 |
oct | 1513321327653 |
9 | 354163540211 |
10 | 113200443307 |
11 | 4400a776586 |
12 | 19b32723977 |
13 | a8a0592443 |
14 | 569c285c27 |
15 | 2e28082157 |
hex | 1a5b45afab |
113200443307 has 32 divisors (see below), whose sum is σ = 133327332864. Its totient is φ = 94097203200.
The previous prime is 113200443287. The next prime is 113200443341. The reversal of 113200443307 is 703344002311.
It is not a de Polignac number, because 113200443307 - 215 = 113200410539 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113200444307) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25602957 + ... + 25607377.
It is an arithmetic number, because the mean of its divisors is an integer number (4166479152).
Almost surely, 2113200443307 is an apocalyptic number.
113200443307 is a deficient number, since it is larger than the sum of its proper divisors (20126889557).
113200443307 is a wasteful number, since it uses less digits than its factorization.
113200443307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5059.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 113200443307 its reverse (703344002311), we get a palindrome (816544445618).
The spelling of 113200443307 in words is "one hundred thirteen billion, two hundred million, four hundred forty-three thousand, three hundred seven".
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