Base | Representation |
---|---|
bin | 10101000101111100… |
… | …01011100110101001 |
3 | 1002020012101010021021 |
4 | 22202332023212221 |
5 | 141142440102131 |
6 | 5111403412441 |
7 | 550423431130 |
oct | 124276134651 |
9 | 32205333237 |
10 | 11324144041 |
11 | 4891203031 |
12 | 2240524121 |
13 | 10b6129b62 |
14 | 795d6a917 |
15 | 46426be11 |
hex | 2a2f8b9a9 |
11324144041 has 16 divisors (see below), whose sum is σ = 13379411584. Its totient is φ = 9382915584.
The previous prime is 11324144011. The next prime is 11324144063. The reversal of 11324144041 is 14044142311.
It is not a de Polignac number, because 11324144041 - 27 = 11324143913 is a prime.
It is a super-2 number, since 2×113241440412 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11324143997 and 11324144015.
It is not an unprimeable number, because it can be changed into a prime (11324144011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 164730 + ... + 223123.
It is an arithmetic number, because the mean of its divisors is an integer number (836213224).
Almost surely, 211324144041 is an apocalyptic number.
It is an amenable number.
11324144041 is a deficient number, since it is larger than the sum of its proper divisors (2055267543).
11324144041 is an equidigital number, since it uses as much as digits as its factorization.
11324144041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 388000.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 11324144041 its reverse (14044142311), we get a palindrome (25368286352).
The spelling of 11324144041 in words is "eleven billion, three hundred twenty-four million, one hundred forty-four thousand, forty-one".
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