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113300120130113 = 7241170351394249
BaseRepresentation
bin11001110000101110111101…
…011010011101001001000001
3112212011101102011210022211202
4121300232331122131021001
5104322302121223130423
61040545205011150545
732602443412012010
oct3160567532351101
9485141364708752
10113300120130113
11331123470a3754
121085a3a4ba5455
134b2b2037a1167
141dd9a7dccaa77
15d172e1e44728
hex670bbd69d241

113300120130113 has 16 divisors (see below), whose sum is σ = 130024230336000. Its totient is φ = 96710611392000.

The previous prime is 113300120130103. The next prime is 113300120130137. The reversal of 113300120130113 is 311031021003311.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113300120130113 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (113300120130103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 287185013 + ... + 287579261.

It is an arithmetic number, because the mean of its divisors is an integer number (8126514396000).

Almost surely, 2113300120130113 is an apocalyptic number.

It is an amenable number.

113300120130113 is a deficient number, since it is larger than the sum of its proper divisors (16724110205887).

113300120130113 is a wasteful number, since it uses less digits than its factorization.

113300120130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 564848.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113300120130113 its reverse (311031021003311), we get a palindrome (424331141133424).

The spelling of 113300120130113 in words is "one hundred thirteen trillion, three hundred billion, one hundred twenty million, one hundred thirty thousand, one hundred thirteen".

Divisors: 1 7 241 1687 170351 394249 1192457 2759743 41054591 95014009 287382137 665098063 67160711399 470124979793 16185731447159 113300120130113