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113304434131 = 744364756473
BaseRepresentation
bin110100110000101111…
…0000111010111010011
3101211110101021121211101
41221201132013113103
53324021413343011
6124015031125231
711120534541130
oct1514136072723
9354411247741
10113304434131
1144063443409
1219b61513817
13a8b8ca2585
1456abdd5587
152e322742c1
hex1a617875d3

113304434131 has 16 divisors (see below), whose sum is σ = 129985979904. Its totient is φ = 96747378624.

The previous prime is 113304434123. The next prime is 113304434207. The reversal of 113304434131 is 131434403311.

It is a cyclic number.

It is not a de Polignac number, because 113304434131 - 23 = 113304434123 is a prime.

It is a super-2 number, since 2×1133044341312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113304434131.

It is not an unprimeable number, because it can be changed into a prime (113304444131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1978111 + ... + 2034583.

It is an arithmetic number, because the mean of its divisors is an integer number (8124123744).

Almost surely, 2113304434131 is an apocalyptic number.

113304434131 is a deficient number, since it is larger than the sum of its proper divisors (16681545773).

113304434131 is an equidigital number, since it uses as much as digits as its factorization.

113304434131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57570.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 113304434131 its reverse (131434403311), we get a palindrome (244738837442).

The spelling of 113304434131 in words is "one hundred thirteen billion, three hundred four million, four hundred thirty-four thousand, one hundred thirty-one".

Divisors: 1 7 443 647 3101 4529 56473 286621 395311 2006347 25017539 36538031 175122773 255766217 16186347733 113304434131